3.1038 \(\int \frac{1}{x^3 (a+b x^n)^2 (c+d x^n)} \, dx\)

Optimal. Leaf size=145 \[ \frac{b (2 a d (n+1)-b c (n+2)) \, _2F_1\left (1,-\frac{2}{n};-\frac{2-n}{n};-\frac{b x^n}{a}\right )}{2 a^2 n x^2 (b c-a d)^2}-\frac{d^2 \, _2F_1\left (1,-\frac{2}{n};-\frac{2-n}{n};-\frac{d x^n}{c}\right )}{2 c x^2 (b c-a d)^2}+\frac{b}{a n x^2 (b c-a d) \left (a+b x^n\right )} \]

[Out]

b/(a*(b*c - a*d)*n*x^2*(a + b*x^n)) + (b*(2*a*d*(1 + n) - b*c*(2 + n))*Hypergeometric2F1[1, -2/n, -((2 - n)/n)
, -((b*x^n)/a)])/(2*a^2*(b*c - a*d)^2*n*x^2) - (d^2*Hypergeometric2F1[1, -2/n, -((2 - n)/n), -((d*x^n)/c)])/(2
*c*(b*c - a*d)^2*x^2)

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Rubi [A]  time = 0.21373, antiderivative size = 145, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 3, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.136, Rules used = {504, 597, 364} \[ \frac{b (2 a d (n+1)-b c (n+2)) \, _2F_1\left (1,-\frac{2}{n};-\frac{2-n}{n};-\frac{b x^n}{a}\right )}{2 a^2 n x^2 (b c-a d)^2}-\frac{d^2 \, _2F_1\left (1,-\frac{2}{n};-\frac{2-n}{n};-\frac{d x^n}{c}\right )}{2 c x^2 (b c-a d)^2}+\frac{b}{a n x^2 (b c-a d) \left (a+b x^n\right )} \]

Antiderivative was successfully verified.

[In]

Int[1/(x^3*(a + b*x^n)^2*(c + d*x^n)),x]

[Out]

b/(a*(b*c - a*d)*n*x^2*(a + b*x^n)) + (b*(2*a*d*(1 + n) - b*c*(2 + n))*Hypergeometric2F1[1, -2/n, -((2 - n)/n)
, -((b*x^n)/a)])/(2*a^2*(b*c - a*d)^2*n*x^2) - (d^2*Hypergeometric2F1[1, -2/n, -((2 - n)/n), -((d*x^n)/c)])/(2
*c*(b*c - a*d)^2*x^2)

Rule 504

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> -Simp[(b*(e*x
)^(m + 1)*(a + b*x^n)^(p + 1)*(c + d*x^n)^(q + 1))/(a*e*n*(b*c - a*d)*(p + 1)), x] + Dist[1/(a*n*(b*c - a*d)*(
p + 1)), Int[(e*x)^m*(a + b*x^n)^(p + 1)*(c + d*x^n)^q*Simp[c*b*(m + 1) + n*(b*c - a*d)*(p + 1) + d*b*(m + n*(
p + q + 2) + 1)*x^n, x], x], x] /; FreeQ[{a, b, c, d, e, m, n, q}, x] && NeQ[b*c - a*d, 0] && LtQ[p, -1] && In
tBinomialQ[a, b, c, d, e, m, n, p, q, x]

Rule 597

Int[(((g_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((e_) + (f_.)*(x_)^(n_)))/((c_) + (d_.)*(x_)^(n_)), x_Sy
mbol] :> Int[ExpandIntegrand[((g*x)^m*(a + b*x^n)^p*(e + f*x^n))/(c + d*x^n), x], x] /; FreeQ[{a, b, c, d, e,
f, g, m, n, p}, x]

Rule 364

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a^p*(c*x)^(m + 1)*Hypergeometric2F1[-
p, (m + 1)/n, (m + 1)/n + 1, -((b*x^n)/a)])/(c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rubi steps

\begin{align*} \int \frac{1}{x^3 \left (a+b x^n\right )^2 \left (c+d x^n\right )} \, dx &=\frac{b}{a (b c-a d) n x^2 \left (a+b x^n\right )}-\frac{\int \frac{a d n-b c (2+n)-b d (2+n) x^n}{x^3 \left (a+b x^n\right ) \left (c+d x^n\right )} \, dx}{a (b c-a d) n}\\ &=\frac{b}{a (b c-a d) n x^2 \left (a+b x^n\right )}-\frac{\int \left (\frac{b (2 a d (1+n)-b c (2+n))}{(b c-a d) x^3 \left (a+b x^n\right )}+\frac{a d^2 n}{(-b c+a d) x^3 \left (c+d x^n\right )}\right ) \, dx}{a (b c-a d) n}\\ &=\frac{b}{a (b c-a d) n x^2 \left (a+b x^n\right )}+\frac{d^2 \int \frac{1}{x^3 \left (c+d x^n\right )} \, dx}{(b c-a d)^2}-\frac{(b (2 a d (1+n)-b c (2+n))) \int \frac{1}{x^3 \left (a+b x^n\right )} \, dx}{a (b c-a d)^2 n}\\ &=\frac{b}{a (b c-a d) n x^2 \left (a+b x^n\right )}+\frac{b (2 a d (1+n)-b c (2+n)) \, _2F_1\left (1,-\frac{2}{n};-\frac{2-n}{n};-\frac{b x^n}{a}\right )}{2 a^2 (b c-a d)^2 n x^2}-\frac{d^2 \, _2F_1\left (1,-\frac{2}{n};-\frac{2-n}{n};-\frac{d x^n}{c}\right )}{2 c (b c-a d)^2 x^2}\\ \end{align*}

Mathematica [A]  time = 0.152146, size = 136, normalized size = 0.94 \[ \frac{b c \left (a+b x^n\right ) (2 a d (n+1)-b c (n+2)) \, _2F_1\left (1,-\frac{2}{n};\frac{n-2}{n};-\frac{b x^n}{a}\right )-a \left (a d^2 n \left (a+b x^n\right ) \, _2F_1\left (1,-\frac{2}{n};\frac{n-2}{n};-\frac{d x^n}{c}\right )+2 b c (a d-b c)\right )}{2 a^2 c n x^2 (b c-a d)^2 \left (a+b x^n\right )} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(x^3*(a + b*x^n)^2*(c + d*x^n)),x]

[Out]

(b*c*(2*a*d*(1 + n) - b*c*(2 + n))*(a + b*x^n)*Hypergeometric2F1[1, -2/n, (-2 + n)/n, -((b*x^n)/a)] - a*(2*b*c
*(-(b*c) + a*d) + a*d^2*n*(a + b*x^n)*Hypergeometric2F1[1, -2/n, (-2 + n)/n, -((d*x^n)/c)]))/(2*a^2*c*(b*c - a
*d)^2*n*x^2*(a + b*x^n))

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Maple [F]  time = 0.135, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{{x}^{3} \left ( a+b{x}^{n} \right ) ^{2} \left ( c+d{x}^{n} \right ) }}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^3/(a+b*x^n)^2/(c+d*x^n),x)

[Out]

int(1/x^3/(a+b*x^n)^2/(c+d*x^n),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} d^{2} \int \frac{1}{{\left (b^{2} c^{2} d - 2 \, a b c d^{2} + a^{2} d^{3}\right )} x^{3} x^{n} +{\left (b^{2} c^{3} - 2 \, a b c^{2} d + a^{2} c d^{2}\right )} x^{3}}\,{d x} +{\left (b^{2} c{\left (n + 2\right )} - 2 \, a b d{\left (n + 1\right )}\right )} \int \frac{1}{{\left (a b^{3} c^{2} n - 2 \, a^{2} b^{2} c d n + a^{3} b d^{2} n\right )} x^{3} x^{n} +{\left (a^{2} b^{2} c^{2} n - 2 \, a^{3} b c d n + a^{4} d^{2} n\right )} x^{3}}\,{d x} + \frac{b}{{\left (a b^{2} c n - a^{2} b d n\right )} x^{2} x^{n} +{\left (a^{2} b c n - a^{3} d n\right )} x^{2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^3/(a+b*x^n)^2/(c+d*x^n),x, algorithm="maxima")

[Out]

d^2*integrate(1/((b^2*c^2*d - 2*a*b*c*d^2 + a^2*d^3)*x^3*x^n + (b^2*c^3 - 2*a*b*c^2*d + a^2*c*d^2)*x^3), x) +
(b^2*c*(n + 2) - 2*a*b*d*(n + 1))*integrate(1/((a*b^3*c^2*n - 2*a^2*b^2*c*d*n + a^3*b*d^2*n)*x^3*x^n + (a^2*b^
2*c^2*n - 2*a^3*b*c*d*n + a^4*d^2*n)*x^3), x) + b/((a*b^2*c*n - a^2*b*d*n)*x^2*x^n + (a^2*b*c*n - a^3*d*n)*x^2
)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{1}{b^{2} d x^{3} x^{3 \, n} + a^{2} c x^{3} +{\left (b^{2} c + 2 \, a b d\right )} x^{3} x^{2 \, n} +{\left (2 \, a b c + a^{2} d\right )} x^{3} x^{n}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^3/(a+b*x^n)^2/(c+d*x^n),x, algorithm="fricas")

[Out]

integral(1/(b^2*d*x^3*x^(3*n) + a^2*c*x^3 + (b^2*c + 2*a*b*d)*x^3*x^(2*n) + (2*a*b*c + a^2*d)*x^3*x^n), x)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{x^{3} \left (a + b x^{n}\right )^{2} \left (c + d x^{n}\right )}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**3/(a+b*x**n)**2/(c+d*x**n),x)

[Out]

Integral(1/(x**3*(a + b*x**n)**2*(c + d*x**n)), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b x^{n} + a\right )}^{2}{\left (d x^{n} + c\right )} x^{3}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^3/(a+b*x^n)^2/(c+d*x^n),x, algorithm="giac")

[Out]

integrate(1/((b*x^n + a)^2*(d*x^n + c)*x^3), x)